x^2-540x-250000=0

Solution for x^2-540x-250000=0 equation:

x^2-540x-250000=0

a = 1; b = -540; c = -250000;
Δ = b2-4ac
Δ = -5402-4·1·(-250000)
Δ = 1291600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1291600}=\sqrt{400*3229}=\sqrt{400}*\sqrt{3229}=20\sqrt{3229}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-540)-20\sqrt{3229}}{2*1}=\frac{540-20\sqrt{3229}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-540)+20\sqrt{3229}}{2*1}=\frac{540+20\sqrt{3229}}{2}
$